Value of (sin 70°)(cot 10° cot 70° − 1)
A short JEE Main 2025 trigonometry problem solved by converting cotangents to cosines and sines, then applying the cos(A+B) identity.
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If sin²10°sin20°sin40°sin50°sin70°=α−1/16sin10°, Find 16+1/α
A five-term trigonometric product from JEE Main 2022, reduced step by step using complementary angles and the sin a cos a identity.
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Value of 36(4cos²9°-1)(4cos²27°-1)(4cos²81°-1)(4cos²243°-1)
A JEE Main 2023 trigonometric product that telescopes to a single value once each factor is rewritten using the sin 3θ triple-angle identity.