If x^((log₂x)² − 6log₂x + 1) = 64, Then x Is Equal To
Solve x^((log₂x)²−6log₂x+1)=64 by taking log base 2 of both sides and substituting t=log₂x, reducing it to a factorable cubic in t.
Solve x^((log₂x)²−6log₂x+1)=64 by taking log base 2 of both sides and substituting t=log₂x, reducing it to a factorable cubic in t.