Let the Range of f(x) = 1/(2 + sin 3x + cos 3x), x ∈ R, Be [a, b]. If α and β Are Respectively the A.M. and the G.M. of a and b, Then α/β Is Equal To
Find the range [a,b] of f(x)=1/(2+sin3x+cos3x), then find α/β where α, β are the AM and GM of a and b, using the fact that sin3x+cos3x ranges over [−√2,√2].
