Let α and β Be the Roots of the Equation x² − 6x − 2 = 0. If aₙ = αⁿ − βⁿ for n ≥ 1, Then the Value of (a₁₀ − 2a₈)/(2a₉) Is Equal To
If α, β are roots of x²−6x−2=0 and an=α^n−β^n, find (a10−2a8)/(2a9) using Newton’s recurrence formula for power sums.