A Square Is Inscribed in the Circle x² + y² − 10x − 6y + 30 = 0. One Side of This Square Is Parallel to y = x + 3. If (xᵢ, yᵢ) Are the Vertices of the Square, Then the Sum of (xᵢ² + yᵢ²) Is Equal To
A square is inscribed in the circle x²+y²−10x−6y+30=0 with one side parallel to y=x+3. Find Σ(xᵢ²+yᵢ²) over the four vertices, using the fact that the square’s diagonals lie along the horizontal and vertical through the centre.
